Impossibile ottenere un oggetto JSON in risposta a una richiesta Ajax con wp_ajax

Question

Impossibile ottenere un oggetto JSON in risposta a una richiesta Ajax con wp_ajax

4

266600 2014-11-17

Ho unproblema con WordPresse Ajax.

Questa è lamiaparte JavaScript (l'hotagliata unpo '):

 var posts = $.ajax({
    type: 'POST',
    url: ajaxurl,
    async: false,
    dataType: 'json',
    data: { action: 'myAjaxFunc' },
    done: function(response) {
        return response;
    }
}).responseText;

$.each(posts, function() {
    $('#someSelect').append( $('<option</option>').text(this.name).val(this.id) );
});

Ilmio codice PHP èil seguente:

 function myAjaxFunc() {

    $posts = get_posts( array(
        'posts_per_page'   => -1,
        'orderby'          => 'title',
        'order'            => 'ASC',
        'post_type'        => 'my-post-type',
        'post_status'      => array( 'publish', 'draft' )
    ) );

    $list = array();
    foreach ( $posts as $post ) {
        $list[] = array(
            'id'   => $post->ID,
            'name' => $post->post_title,
            'link' => get_permalink( $post->ID ),
        );
    }

    header("Content-type: application/json");
    echo json_encode( $list );
    die;
}
add_action( 'wp_ajax_nopriv_myAjaxFunc', 'myAjaxFunc' );
add_action( 'wp_ajax_myAjaxFunc', 'myAjaxFunc' );

Lo script riceve la risposta Ajax da admin-ajax. Sfortunatamente la consolegenera unerrore quando arriva all'istruzione eachnel codice JavaScript ... dice:

 "Uncaught TypeError: Cannot use 'in' operator to search for '4' in Array".

Sefaccio un console.log deimiei "post" var ottengo una stringa 'Array'. Nonimporta comepasso la variabile $listin PHP,restituirà sempre una stringa. La query restituiscepost altrove,quindinon è vuota. Hoprovato senza json_encode,cone senza dichiarazione diintestazione,usando wp_send_json(),mettendo ob_clean()prima diecheggiare l'array,inserendo l'arrayin un array ... Maentra semprein ajax come una stringa Arraye eachnonpuò scorrere attraverso diessa.

Dovrebbeessere una cosamolto semplicee non riesco a capireperchénonfunziona. Non ho altrierrori o avvisi JavaScript o PHPe tuttoil restofunziona correttamente.

I have a problem with WordPress and Ajax.

This is my JavaScript part (I trimmed it a bit):

var posts = $.ajax({
    type: 'POST',
    url: ajaxurl,
    async: false,
    dataType: 'json',
    data: { action: 'myAjaxFunc' },
    done: function(response) {
        return response;
    }
}).responseText;

$.each(posts, function() {
    $('#someSelect').append( $('<option</option>').text(this.name).val(this.id) );
});

My PHP code is as follows:

function myAjaxFunc() {

    $posts = get_posts( array(
        'posts_per_page'   => -1,
        'orderby'          => 'title',
        'order'            => 'ASC',
        'post_type'        => 'my-post-type',
        'post_status'      => array( 'publish', 'draft' )
    ) );

    $list = array();
    foreach ( $posts as $post ) {
        $list[] = array(
            'id'   => $post->ID,
            'name' => $post->post_title,
            'link' => get_permalink( $post->ID ),
        );
    }

    header("Content-type: application/json");
    echo json_encode( $list );
    die;
}
add_action( 'wp_ajax_nopriv_myAjaxFunc', 'myAjaxFunc' );
add_action( 'wp_ajax_myAjaxFunc', 'myAjaxFunc' );

The script gets the Ajax response from admin-ajax. Unfortunately the console throws an error when it gets to the each statement in the JavaScript code... it says:

"Uncaught TypeError: Cannot use 'in' operator to search for '4' in Array".

If I do a console.log of my "posts" var I get a string 'Array'. No matter how I pass the $list variable in PHP it will always return a string. The query returns posts elsewhere, so it's not empty. I tried without json_encode, with and without declaring header, using wp_send_json(), putting ob_clean() before echoing the array, putting the array into an array... But it always gets into ajax as a string Array and each cannot cycle through it.

This should be a very simple thing and I can't understand why it's not working. I don't have other JavaScript or PHP errors or warnings and everything else runs fine.

- Cosa vedi quando vai su http://www.example.com/wp-admin/admin-ajax.php?action=myAjaxFunc
  
  What do you see when you go to http://www.example.com/wp-admin/admin-ajax.php?action=myAjaxFunc
  - 0
  - 2014-11-17
  - czerspalace
- Qualcheprogresso sullatua domanda?Perfavore,potresti seguirci?
  
  Any progress on your question? Could you please follow up?
  - 0
  - 2015-04-15
  - kaiser
- oh ... questo è di 5mesifa ... ho risposto allamia domandatra l'altroilgiorno dopo l'hopostata,usandobit di risposta BODA82 - semplicementenon l'ho contrassegnata come risposta corretta;@toscho ha aggiuntoil suo seguitomoltopiùtardiieri,nonposso verificare se anche la sua risposta èbuona ora,ha sensoperò
  
  oh... this is from 5 months ago... I did answer to my own question by the way the next day I posted it, using bits of BODA82 answer - I just didn't marked it as the correct answer; @toscho added his follow up much later yesterday I can't verify if his answer is also good now, it makes sense though
  - 0
  - 2015-04-16
  - unfulvio

3 risposta

voti

2

2014-11-17

Ci sei quasi con latuafunzione PHP. Non ènecessarioimpostare l'intestazione. (Modifica:inoltre,supponendo che get_posts() stiaeffettivamente restituendo risultati.)

 function myAjaxFunc() {

    $posts = get_posts( array(
        'posts_per_page'   => -1,
        'orderby'          => 'title',
        'order'            => 'ASC',
        'post_type'        => 'my-post-type',
        'post_status'      => array( 'publish', 'draft' )
    ) );

    $list = array();
    foreach ( $posts as $post ) {
        $list[] = array(
            'id'   => $post->ID,
            'name' => $post->post_title,
            'link' => get_permalink( $post->ID ),
        );
    }
    echo json_encode( $list );
    die;
}
add_action( 'wp_ajax_nopriv_myAjaxFunc', 'myAjaxFunc' );
add_action( 'wp_ajax_myAjaxFunc', 'myAjaxFunc' );

Eiltuo Javascript:

 $.ajax({
    url: "<?php bloginfo('url'); ?>/wp-admin/admin-ajax.php",
    type: "POST",
    data: "action=myAjaxFunc",
    success: function(results) {
        var posts = JSON.parse(results);
        console.log(results);
        $.each(posts, function() {
            $('#someSelect').append( $('<option></option>').text(this.name).val(this.id) );
        });
    },
    error: function() {
        console.log('Cannot retrieve data.');
    }
});

Almost there with your PHP function. No need to set the header. (Edit: Also, assuming get_posts() is actually returning results.)

function myAjaxFunc() {

    $posts = get_posts( array(
        'posts_per_page'   => -1,
        'orderby'          => 'title',
        'order'            => 'ASC',
        'post_type'        => 'my-post-type',
        'post_status'      => array( 'publish', 'draft' )
    ) );

    $list = array();
    foreach ( $posts as $post ) {
        $list[] = array(
            'id'   => $post->ID,
            'name' => $post->post_title,
            'link' => get_permalink( $post->ID ),
        );
    }
    echo json_encode( $list );
    die;
}
add_action( 'wp_ajax_nopriv_myAjaxFunc', 'myAjaxFunc' );
add_action( 'wp_ajax_myAjaxFunc', 'myAjaxFunc' );

And your Javascript:

$.ajax({
    url: "<?php bloginfo('url'); ?>/wp-admin/admin-ajax.php",
    type: "POST",
    data: "action=myAjaxFunc",
    success: function(results) {
        var posts = JSON.parse(results);
        console.log(results);
        $.each(posts, function() {
            $('#someSelect').append( $('<option></option>').text(this.name).val(this.id) );
        });
    },
    error: function() {
        console.log('Cannot retrieve data.');
    }
});

fonte
BODA82

Quando salvi alcuni dati usando JSON.stringify ()e poi devi leggerliin php.Il codice seguente hafunzionatoperme.json_decode (html_entity_decode (stripeslashes ($jsonString)));

When you save some data using JSON.stringify() and then need to read that in php. The following code worked for me. json_decode( html_entity_decode( stripslashes ($jsonString ) ) );
- 0
- 2019-12-04
- Vishal Tanna

2

2015-04-15

C'è una via d'uscita.Utilizza completeinvece di success o done:

 posts = $.ajax({
    type: 'GET',
    url: ajaxurl,
    async: false,
    dataType: 'json',
    data: { action : 'getHotelsList' },
    complete: function(results) {

Eprova a rimuovere async:false seilproblemapersiste.

There is a way out. Use complete instead of success or done:

posts = $.ajax({
    type: 'GET',
    url: ajaxurl,
    async: false,
    dataType: 'json',
    data: { action : 'getHotelsList' },
    complete: function(results) {

And try to remove async:false if the problem persists.

unfulvio · Accepted Answer · 2014-11-18

8

2014-11-18

La risposta di BODA82 ha aiutato,ma allafine mi sono reso conto che avrei dovuto sostituire responseText conilmetodo responseJSONnelmio codice JavaScript. Nell'esempio seguente stavomemorizzandoi risultati della risposta Ajaxin una variabile. Non sapevo cifosse unmetodo specificoper ottenere la rispostain JSON. In questomodo l'oggetto/array coni risultati di get_posts() viene restituito correttamentee non come una stringa:

 posts = $.ajax({
    type: 'GET',
    url: ajaxurl,
    async: false,
    dataType: 'json',
    data: { action : 'getHotelsList' },
    done: function(results) {
        // Uhm, maybe I don't even need this?
        JSON.parse(results);
        return results;
    },
    fail: function( jqXHR, textStatus, errorThrown ) {
        console.log( 'Could not get posts, server response: ' + textStatus + ': ' + errorThrown );
    }
   }).responseJSON; // <-- this instead of .responseText

Notapersonale,ma anche consigliogenerale: senon riesci a sistemare qualcosa la sera è un segno che dovresti andare a letto,leggere un libroe contare le stelle. Una risposta verràtrovata lamattina successiva,prima èmeglio è: D

BODA82's answer helped, but eventually I realized that I should have replaced responseText with responseJSON method in my JavaScript code. In the example below I was storing the Ajax response results in a variable. I didn't know there was a specific method to get the response in JSON. In a such way the object/array with get_posts() results is returned correctly and not as a string:

posts = $.ajax({
    type: 'GET',
    url: ajaxurl,
    async: false,
    dataType: 'json',
    data: { action : 'getHotelsList' },
    done: function(results) {
        // Uhm, maybe I don't even need this?
        JSON.parse(results);
        return results;
    },
    fail: function( jqXHR, textStatus, errorThrown ) {
        console.log( 'Could not get posts, server response: ' + textStatus + ': ' + errorThrown );
    }
   }).responseJSON; // <-- this instead of .responseText

Note to self, but also general advice: if you can't fix something in the evening it's a sign you should go to bed, read a book, and count stars. An answer will be found the next morning, the earlier the better :D