Come faccio a codificare in base58 l'ID della catena usando Python?

Question

Come faccio a codificare in base58 l'ID della catena usando Python?

- 7
- 199 2019-02-16
Quando Tezos devefirmare unpayload di un'operazione di cottura o di approvazione,ilbyte 0 sarà 0x01per un'operazione di cottura o 0x02per un'operazione di approvazione. Ibyte 1-5nelpayload dell'operazione contengono l'ID della catena (altrimentinoto come Rete),chepuòessere codificatoin base58 utilizzando questa specifica :

let chain_id="\ 087 \ 082 \ 000" (* Net (15) *)

L'ID della catena risultante sarà una stringa come NetXdQprcVkpaWU (l'ID della catenamainnet attualmente attivo al 16febbraio 2019).

Comeposso convertireil campo a 4bytein byte 1-5nelformato Net (15) codificatobase58 utilizzandoilmodulopybitcointools di Vitalik?

Hoprovato a utilizzare lo scriptin scripts/b58_prefix.py per determinareilmagicbyte appropriato dapassare allafunzione bitcoin.bin_to_b58check ,manon ottengoil risultato appropriato:

$ ./b58_prefix.py Net 4 15 5722583 [87L,81L,215L]

Eccoilmio codice:

defget_chain_id (self): chainid=bytes.fromhex (self.payload [2:10]) returnbitcoin.bin_to_b58check (chainid,magicbyte=5722583)

Su zeronet,unpayload di approvazione è simile a questo: 023bb717ee882891d7be5b881cefa98946800e3d67b5d01b4237b3618709defb51ec37c3e100000518ae ,dove 3bb717ee è l'ID della catena e YFU dovrebbeessere NetXSzLHKwSumh7 su zeronet.
When Tezos needs to sign a baking or endorsement operation payload, byte 0 will be a 0x01 for a baking operation or 0x02 for an endorsement operation. Bytes 1-5 in the operation payload contain the chain ID (otherwise known as Network), which can be encoded in base58 using this specification:

let chain_id = "\087\082\000" (* Net(15) *)

The resulting chain ID will be a string like NetXdQprcVkpaWU (the currently active mainnet chain ID as of Feb. 16th, 2019).

How do I convert the 4-byte field in bytes 1-5 into the base58 encoded Net(15) format using Vitalik's pybitcointools module?

I've tried using the script in scripts/b58_prefix.py to determine the appropriate magicbyte to pass to the bitcoin.bin_to_b58check function, but I'm not getting the appropriate result:

$ ./b58_prefix.py Net 4 15 5722583 [87L, 81L, 215L]

Here is my code:

def get_chain_id(self): chainid = bytes.fromhex(self.payload[2:10]) return bitcoin.bin_to_b58check(chainid, magicbyte=5722583)

On zeronet, an endorsement payload looks like this: 023bb717ee882891d7be5b881cefa98946800e3d67b5d01b4237b3618709defb51ec37c3e100000518ae, where 3bb717ee is the chain id, but that converts to Net1BPz7FKbUqsY and it should be NetXSzLHKwSumh7 on zeronet.

protocol encoding base58 python

fonte

Luke Youngblood

3 risposta

voti

5

2019-02-17

Iltuomagicbyte sembraessere sbagliato.Seprendii valori deibyte decimali dall'originale,li convertiin esadecimale,quindi aggiungi uno zeroiniziale,ottieni

>>> struct.unpack('>L', b'\x00\x57\x52\x00')[0] 5722624

Questo valore dovrebbeprodurreil risultato atteso:

>>> payload = '023bb717ee882891d7be5b881cefa98946800e3d67b5d01b4237b3618709defb51ec37c3e100000518ae' >>> mb = struct.unpack('>L', b'\x00\x57\x52\x00')[0] >>> chainid = bytes.fromhex(payload[2:10]) >>> bitcoin.bin_to_b58check(chainid, magicbyte=mb) 'NetXSzLHKwSumh7'

Your magicbyte seems to be wrong. If you take the decimal byte values from the original, convert them to hex, then pad it with a leading zero, you get

>>> struct.unpack('>L', b'\x00\x57\x52\x00')[0] 5722624

This value should produce the expected result:

>>> payload = '023bb717ee882891d7be5b881cefa98946800e3d67b5d01b4237b3618709defb51ec37c3e100000518ae' >>> mb = struct.unpack('>L', b'\x00\x57\x52\x00')[0] >>> chainid = bytes.fromhex(payload[2:10]) >>> bitcoin.bin_to_b58check(chainid, magicbyte=mb) 'NetXSzLHKwSumh7'

fonte

cayblood

Sì 5722624 èilmagicbytegiusto:

Yeah 5722624 is the right magicbyte:

1

2019-02-17

Stephen Andrews

4

2019-02-16

Sembra chetu stiaeffettivamente acquisendo solo 2byte di dati (4 caratteriesadecimali).L'ho verificato decodificandoil risultato ottenutoe restituendo solo duebyte di datiperilbytemagico specificato.

Prova ad apportare la seguentemodifica:

def get_chain_id(self): chainid = bytes.fromhex(self.payload[2:10]) return bitcoin.bin_to_b58check(chainid, magicbyte=5722583)

It looks like you are only actually grabbing 2 bytes of data (4 hex chars). I verified this by decoding the result you got, and it only returning two bytes of data for the given magic byte.

Try making the following change:

def get_chain_id(self): chainid = bytes.fromhex(self.payload[2:10]) return bitcoin.bin_to_b58check(chainid, magicbyte=5722583)

fonte

Stephen Andrews

Grazie,questofaparte delproblema: devoprendere 8 caratteri (4byteesadecimali) o `self.payload [2:10]`.Su zeronet,unpayload di approvazione hail seguente aspetto: `023bb717ee882891d7be5b881cefa98946800e3d67b5d01b4237b3618709defb51ec37c3e100000518ae`,dove` 3bb717ee` è l'id della catena,ma viene convertitoin `Net1BUqS7` Homodificato unpo 'la domanda sopra.Grazie ancorapertuttoil vostro aiuto.

Thanks, this is part of the problem - I need to grab 8 characters (4 hex bytes), or `self.payload[2:10]`. On zeronet, an endorsement payload looks like this: `023bb717ee882891d7be5b881cefa98946800e3d67b5d01b4237b3618709defb51ec37c3e100000518ae`, where `3bb717ee` is the chain id, but that converts to `Net1BPz7FKbUqsY` and it should be `NetXSzLHKwSumh7` on zeronet. I edited the question above a bit. Thanks again for all your help.

1

2019-02-17

Luke Youngblood

2

2019-02-26

Prima ditutto,moltegrazie!Mi hai aiutato a risolvereilmistero dellafirma delblocco :) Puoi utilizzareilpacchetto pytezos.encoding :

from pytezos.encoding import base58_encode def get_chain_id(self): chainid = bytes.fromhex(self.payload[2:10]) return base58_encode(chain_id, b'Net')

First of all, many thanks! You've helped me with solving the block signature mystery :) You can use pytezos.encoding package:

from pytezos.encoding import base58_encode def get_chain_id(self): chainid = bytes.fromhex(self.payload[2:10]) return base58_encode(chain_id, b'Net')

fonte

Michael Zaikin

cayblood · Accepted Answer · 2019-02-17

5

2019-02-17

Iltuomagicbyte sembraessere sbagliato.Seprendii valori deibyte decimali dall'originale,li convertiin esadecimale,quindi aggiungi uno zeroiniziale,ottieni

 >>> struct.unpack('>L', b'\x00\x57\x52\x00')[0]
5722624

Questo valore dovrebbeprodurreil risultato atteso:

 >>> payload = '023bb717ee882891d7be5b881cefa98946800e3d67b5d01b4237b3618709defb51ec37c3e100000518ae'
>>> mb = struct.unpack('>L', b'\x00\x57\x52\x00')[0]
>>> chainid = bytes.fromhex(payload[2:10])
>>> bitcoin.bin_to_b58check(chainid, magicbyte=mb)
'NetXSzLHKwSumh7'

Your magicbyte seems to be wrong. If you take the decimal byte values from the original, convert them to hex, then pad it with a leading zero, you get

>>> struct.unpack('>L', b'\x00\x57\x52\x00')[0]
5722624

This value should produce the expected result:

>>> payload = '023bb717ee882891d7be5b881cefa98946800e3d67b5d01b4237b3618709defb51ec37c3e100000518ae'
>>> mb = struct.unpack('>L', b'\x00\x57\x52\x00')[0]
>>> chainid = bytes.fromhex(payload[2:10])
>>> bitcoin.bin_to_b58check(chainid, magicbyte=mb)
'NetXSzLHKwSumh7'

Sì 5722624 èilmagicbytegiusto:

Yeah 5722624 is the right magicbyte:
- 1
- 2019-02-17
- Stephen Andrews