prefissi base58

Question

prefissi base58

- 4
- 187 2019-02-01
Ilmodulo Prefixin src/lib_crypto/base58.ml ha linee come let ed25519_public_key_hash = "\006\161\159" (* tz1(36) *).

Come si ottiene "\006\161\159" da tz1(36)?

Module Prefix in src/lib_crypto/base58.ml has lines such as let ed25519_public_key_hash = "\006\161\159" (* tz1(36) *).

How does one get "\006\161\159" from tz1(36)?

crypto base58

2 risposta

voti

- 3
- 2019-02-01
Iprefissi Base58produrranno sempre un outputprefissatoper una determinata lunghezza di output.Quindi l'indirizzo diinput è di 20byte +ilprefisso di 3bytefornisce unindirizzo lungo 36 caratteri contz1.

Puoi calcolare questiprefissiindovinandoe verificando.

Base58 prefixes will always produce a prefixed output for a set length of output. So the input address is 20 bytes + the 3 byte prefix gives a 36 char long address with tz1.

You calculate these prefixes by guess and check.

Arthur B · Accepted Answer · 2019-02-01

7

2019-02-01

Base58 codificai caratteri aggiungendo unprefisso,trattandoi byte come unnumerobig endiane scrivendo quelnumerobig endianin base 58.

Pertanto,prefissi specificipossonoindividuare le "cifre"più significativein Base58.

Lo scriptpython b58_prefix.pynella directory scripts del repository Tezospuò aiutare atrovare queiprefissi.Nota chepereseguirlo avraibisogno di questa versione della libpython pybitcointools

 pip install git+https://github.com/vbuterin/pybitcointools.git@aeb0a2bbb8bbfe421432d776c649650eaeb882a5#egg=master

Base58 encodes characters by appending a prefix, treating the bytes as a big endian number and writing that big endian number in base 58.

Therefore, specific prefixes can pin down the most significant "digits" in Base58.

The python script b58_prefix.py in the scripts directory of the Tezos repo can help find those prefixes. Note that to run it you will need this version of the python lib pybitcointools

pip install git+https://github.com/vbuterin/pybitcointools.git@aeb0a2bbb8bbfe421432d776c649650eaeb882a5#egg=master

Come si converte l'array dibyte "" \ 006 \ 161 \ 159 ""in un valoremagicbyte chepuòesserepassato allafunzionebitcoin.bin_to_b58check? Ho scoperto chepuoi usare struct.unpack coni valoriesadecimali dell'array dibytein questomodo (generap2sig (98)) `P256_SIGNATURE=struct.unpack ('> L',b '\ x36 \ xF0 \ x2C \ x34')[0] `,ma" "\ 006 \ 161 \ 159" "è di soli 3byte,quindinonpuòessere compressoin uninterobig-endian a 4byte.

How do you convert the byte array `"\006\161\159"` into a magicbyte value that can be passed to the bitcoin.bin_to_b58check function? I discovered that you can use struct.unpack with the hex values of the byte array like this (generates p2sig(98))`P256_SIGNATURE = struct.unpack('>L', b'\x36\xF0\x2C\x34')[0]`, but `"\006\161\159"` is only 3 bytes so it can't be packed into a 4-byte big-endian integer.
- 0
- 2019-02-16
- Luke Youngblood
vedere ancheil MRin attesa https://gitlab.com/tezos/tezos/-/merge_requests/1528 che documenta ulteriormente questo script.

see also the pending MR https://gitlab.com/tezos/tezos/-/merge_requests/1528 that documents this script further.
- 0
- 2020-04-08
- arvidj